leetcode 27 Remove Element-白红宇

Remove Element

Total Accepted: 60351

Total Submissions: 187833

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

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c++ 解决方案：

class Solution {public:    int removeElement(vector
        
         & nums, int val) {        int n = nums.size();        int i = 0;        while( i < n ) {             if( nums[i] == val ) {                swap(nums[i], nums[n-1]);                n--;            } else {                i++;            }        }        return n;    }};

int removeElement(vector
        
         & nums, int val){    vector
         
          ::iterator  itr = nums.begin();    while (itr != nums.end())    {        if (*itr == val)            itr = nums.erase(itr);        else            ++itr;    }    return nums.size();}

int removeElement(int A[], int n, int elem) {    int begin=0;    for(int i=0;i

python解决方案：

class Solution:# @param    A       a list of integers# @param    elem    an integer, value need to be removed# @return an integerdef removeElement(self, A, elem):    i = 0    for j in range(len(A)):        if A[j] != elem:            A[i] = A[j]            i += 1    return i

史上最简洁的解决方案：

def removeElement(self, nums, val):        nums[:] = [x for x in nums if x!=val]        return len(nums)